http://stackoverflow.com/questions/8564896/fastest-way-to-check-if-a-string-can-be-parsed-to-double-in-java
final String Digits = "(\\p{Digit}+)";
final String HexDigits = "(\\p{XDigit}+)";
// an exponent is 'e' or 'E' followed by an optionally
// signed decimal integer.
final String Exp = "[eE][+-]?" + Digits;
final String fpRegex = ("[\\x00-\\x20]*" + // Optional leading
// "whitespace"
"[+-]?(" + // Optional sign character
"NaN|" + // "NaN" string
"Infinity|" + // "Infinity" string
// A decimal floating-point string representing a finite
// positive
// number without a leading sign has at most five basic pieces:
// Digits . Digits ExponentPart FloatTypeSuffix
//
// Since this method allows integer-only strings as input
// in addition to strings of floating-point literals, the
// two sub-patterns below are simplifications of the grammar
// productions from the Java Language Specification, 2nd
// edition, section 3.10.2.
// Digits ._opt Digits_opt ExponentPart_opt FloatTypeSuffix_opt
"(((" + Digits + "(\\.)?(" + Digits + "?)(" + Exp + ")?)|" +
// . Digits ExponentPart_opt FloatTypeSuffix_opt
"(\\.(" + Digits + ")(" + Exp + ")?)|" +
// Hexadecimal strings
"((" +
// 0[xX] HexDigits ._opt BinaryExponent FloatTypeSuffix_opt
"(0[xX]" + HexDigits + "(\\.)?)|" +
// 0[xX] HexDigits_opt . HexDigits BinaryExponent
// FloatTypeSuffix_opt
"(0[xX]" + HexDigits + "?(\\.)" + HexDigits + ")" +
")[pP][+-]?" + Digits + "))" + "[fFdD]?))" + "[\\x00-\\x20]*");// Optional
// trailing
// "whitespace"
if (Pattern.matches(fpRegex, val))
Double.valueOf(val); // Will not throw NumberFormatException
else {
// Perform suitable alternative action
}
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